Answer: 0.25
Step-by-step explanation:
The data we have is:
Slacks: one brown, one black.
Sweaters: one tan, one red, one white.
Shirts: one white, one gray.
If the clothes are selected at random, then the probability that Julie will wear brown slacks is equal to the number of brown slacks, divided the total number of slacks.
We have 1 brown slack and 2 slacks in total, so the probability is:
p1 = 1/2 = 0.5
We do the same for the white shirt, we have 2 shirts and one is white, so the probability is:
p2 = 1/2 = 0.5
And we do not have any condition in the sweater, so we can ignore that selection.
Then the probability of both events happening at the same time (that Julie will wear brown slacks and a white shirt) is equal to the product of the individual probabilities: P = p1*p2 = 0.5*0.5 = 0.25
This in what I got:
(-7i)(10i)
-70i
Answer:
50
Step-by-step explanation:
1÷6×150=25
1÷6×150=25
ans:25+25
=50
<span>You are to find the maximum amount of baggage that may be loaded aboard the airplane for the cg (center of gravity) to remain within the moment envelope.
In order to solve this, there is a graph that shows the load weight and the load moment of pilot and front passenger, fuel, rear passenger and passenger including the baggage. Using the given data such as pilot and front passenger 250, the load moment is 9 lbs/in, for the rear passenger at 400lbs, the load moment is 28.5 lbs/in, the fuel at 30 gal has a load moment of 2 lbs/in and oil at 8 quarters is 15 lbs. The total weight is 1,350 + 250 + 400 + 15 is 2015 lbs.</span>
Answer:3/5
Step-by-step explanation:
20 papers in total
12 boy papers
12/20
simplified to 3/5