It’s b) an =-125(-^2/5)^n
Answer:
The probability is 0.95
Step-by-step explanation:
In this question, we are interested in calculating the probability that a randomly selected student of the university recycles at least some of the times
Mathematically, the probability that student recycles at least some of time = 1 - probability that the student never recycles all the time
From the question, the probability that the student never recycles all the time = 0.05
Substituting this into the equation given above;
Probability that a randomly selected student at the university recycles at least some of the time = 1-0.05 = 0.95
9514 1404 393
Answer:
(X, Y, Z) = (-2, 3, 3)
Step-by-step explanation:
We can subtract the second equation from the first to get ...
Y -Z = 0
We can add the third equation to the first to get ...
Z = 3
Then ...
Y -3 = 0 ⇒ Y = 3
and ...
X -3 -2(3) = -11
X = -2 . . . . . . . . . add 9
The solution is ...
(X, Y, Z) = (-2, 3, 3)
To solve for proportion we make use of the z statistic.
The procedure is to solve for the value of the z score and then locate for the
proportion using the standard distribution tables. The formula for z score is:
z = (X – μ) / σ
where X is the sample value, μ is the mean value and σ is
the standard deviation
when X = 70
z1 = (70 – 100) / 15 = -2
Using the standard distribution tables, proportion is P1
= 0.0228
when X = 130
z2 = (130 – 100) /15 = 2
Using the standard distribution tables, proportion is P2
= 0.9772
Therefore the proportion between X of 70 and 130 is:
P (70<X<130) = P2 – P1
P (70<X<130) = 0.9772 - 0.0228
P (70<X<130) = 0.9544
Therefore 0.9544 or 95.44% of the test takers scored
between 70 and 130.
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
