2 years ago

What is the radius of a circle with a diameter of 6 meters

Mathematics

2 answers:

Tpy6a [65]2 years ago

8 0

3 meters
radius = d/2

Hope this helps ;)

FromTheMoon [43]2 years ago

7 0

Answer:

the radius is 3 m

Step-by-step explanation:

the radius of a circle is always one half of the diameter.

Here the diameter is 6 m, so the radius is 3 m.

You might be interested in

3. Find the geometric mean of 4 and 10. (1 point) A. 20 B. 7 C. SQ root of 14 D. 2x SQ root of 10

mart [117]

Answer:

$2\sqrt10$

6.3 to the nearest 10th

Step-by-step explanation:

Hope this helped :)

7 0

2 years ago

11+3(9-6)-4=<br> Please do it step by step.

tester [92]

11+3=14*(9-6=3)-4=38

3 0

2 years ago

Read 2 more answers

Solve the given equation by completing the square.

klasskru [66]

Answer:

Step-by-step explanation:

$x^2+8x=38\\\\x^2+8x-38=0\\\\\Delta=8^2+4*38=216=6^3\\\\x=\dfrac{-8-6\sqrt{6} }{2} \ or\ x=\dfrac{-8+6\sqrt{6} }{2}\\\\x=-4-3\sqrt{6} \ or\ x=-4+3\sqrt{6}\\\\a=-4\\b=3\\c=6\\$

3 0

2 years ago

Marilyn selects a piece of candy at random from a

ki77a [65]

Answer: 9/14

Step-by-step explanation: 4+3+2/4+5+3+2 = 9/14

3 0

1 year ago

A 5.00 L air sample has a pressure of 107 kPa at a temperature of -50C. If the temperature is raised to 102C and the volume expa

joja [24]

Answer:

129.9 kPa

Step-by-step explanation:

The relationship between temperature T, volume V and pressure P is given by the ideal gas equation which is given as

K = PV/T where K is a constant such that were there is a change of temperature T₁, volume V₁ and pressure P₁ to temperature T₂, volume V₂ and pressure P₂ then the relationship may be given

P₁V₁/T₁ = P₂V₂/T₂

where T is measured in ⁰K

T₁ = -50 + 273

= 223 ⁰K

T₂ = 102 + 273

= 379 ⁰K

5 × 107/223 = P₂ × 7/379

P₂ = 129.9 kPa

7 0

2 years ago