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2 years ago

If comparing x^2 to x^3, which value of x gives the greatest difference:x=6,x=8,x=10?

Mathematics

1 answer:

VMariaS [17]2 years ago

5 0

Answer:

the value of x that gives the greatest difference is 10.

Step-by-step explanation:

Given;

x² and x³

values of x = 6, 8 and 10

When x = 6

6³ - 6² = 216 - 36 = 180

When x = 8

8³ - 8² = 512 - 64 = 448

When x = 10

10³ - 10² = 1000 - 100 = 900

Therefore, the value of x that gives the greatest difference is 10.

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Which point is a solution to the inequality shown in this graph

tiny-mole [99]

Answer: C. (0, -3)

Step-by-step explanation:

You don't even need to find the function, just mentally graph every point in the options on the graph.

If it land in the white area, it's not a solution.
If it land in the blue area or on the line, it's a solution.

<em>The line is not dotted, showing that the inequality is probably either ≥ or ≤, so points on the line do count as solution.</em>

7 0

2 years ago

when Rons truck was full, it weighed 7.5 tons. The weight he carried at that time was 3.25 tons. How many tons does Ron's truck

strojnjashka [21]

7.5-3.25=4.25 tons.

The truck weights 4.25 tons.

Check with other answers, although I'm pretty sure its correct.

Heart if helpful :D

4 0

2 years ago

Find the distance between the two points. Round to the nearest tenth if necessary. (6, 11), (0, 3) a. 10 b. 14 c. 15 d. 100

lorasvet [3.4K]

Answer: option a

Step-by-step explanation:

You must apply the formula for calculate the distance between the two points. which is shown below:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Therefore, keeping on mind that the points given in the problem are (6, 11), (0, 3), when you substitute values into the formula shown above, you obtain that the distance between these two points is the following:

$d=\sqrt{(0-6)^2+(3-11)^2}\\d=10$

8 0

2 years ago

Read 2 more answers

Use the quadratic formula to find the complex solution to the equation 10x^2 - x + 9 = 0.

Jlenok [28]

We have the following:

$10x^2-x+9=0$

solving:

$\begin{gathered} 10x^2-x+9=0 \\ 10x^2-x+9-9=-9 \\ 10x^2-x=-9 \\ \frac{10}{10}x^2-\frac{x}{10}=-\frac{9}{10} \\ x^2-\frac{x}{10}+(-\frac{1}{20})^2=-\frac{9}{10}+(-\frac{1}{20})^2 \\ (x-\frac{1}{20})^2=-\frac{359}{400}\rightarrow(x-\frac{1}{20})=\sqrt[]{-\frac{359}{400}} \\ x=\frac{1}{20}+i\frac{\sqrt{359}}{20} \\ x=\frac{1}{20}-i\frac{\sqrt{359}}{20} \end{gathered}$

The answer is the last option

6 0

3 months ago

Please simplify.

irina [24]

Answer:

B) 1/4c^4

Step-by-step explanation:

Because 3/12=1/4 and c^8/c^12=1/c^4.

5 0

2 years ago