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Artyom0805 [142]

2 years ago

7

A bus starts to move from rest. If it is accelerated by 0.8m/s2, calculate the velocity and distance traveled after 8 s.

1 answer:

Colt1911 [192]2 years ago

6 0

<u>We are given:</u><u>_______________________________________________</u>

Initial velocity (u) = 0 m/s

acceleration (a) = 0.8 m/s²

time interval (t) = 8 seconds

final velocity (v) = v m/s

distance travelled (s) = s m

<u>Solving for the final velocity:</u><u>___________________________________</u>

We know that:

v = u + at [first equation of motion]

v = 0 + (0.8)(8) [replacing the variables]

v = 6.4 m/s

Hence, the final velocity is 6.4 m/s

<u>Solving for the distance travelled:</u><u>_______________________________</u>

We know that:

s = ut + 1/2(at²) [second equation of motion]

s = (0)(8) + 1/2(0.8)(8)(8) [replacing the variables]

s = 1/2(6.4*8)

s = 25.6 m

Hence, the distance travelled is 25.6 m

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