Answer:
Step-by-step explanation:
Given the first two numbers of a sequence as 2, 6...
If it is an arithmetic difference, the common difference will be d = 6-2 = 4
Formula for calculating nth term of an ARITHMETIC sequence Tn = a+(n-1)d
a is the first term = 2
d is the common difference = 4
n is the number if terms
Substituting the given values in the formula.
Nth term Tn = 2+(n-1)4
Tn = 2+4n-4
Tn = 4n-4+2
Tn = 4n-2
2) If the sequence us a geometric sequence
Nth term of the sequence Tn = ar^(n-1)
r is the common ratio
r is gotten by the ratio of the terms I.e
r = T2/T1
r = 6/2
r = 3
Since a = 2
Tn = 2(3)^(n-1)
Hence the nth term of the geometric sequence is Tn = 2(3)^(n-1)
Answer:
the answer is 45.9
Step-by-step explanation:
hope this helps :)
can I plz have brainliest
<span>It's letter C
Addition, you can have 6 + 107 = 113 </span>
<span>Commutative Property by moving: 107 + 6 = 113 </span>
<span>Associative Property by grouping: (3 + 3) + (100 + 7 ) = 113 </span>
<span>Distributive Property by allotting: 2 (3) + 107 = 113 </span>
<span>Multiplication, you can have 6 x 107 = 642 </span>
<span>Commutative Property by moving: 107 x 6 = 642 </span>
<span>Associative Property by grouping: (3 + 3) x (100 + 7 ) = 642 </span>
<span>Distributive Property by allotting: 2(3) x 107 = 642<span>
</span></span>
Answer:
4 en la primera y 28 en la segunda juntos 32
Answer:
Step-by-step explanation:
2 3\4 < b-8/15
add 8\15 to both sides
2 3\4 + 8\15 < b
