Considering the perimeter of the rectangle, we have that the length is of 9 inches and the width is of 55 inches.
<h3>What is the perimeter of a rectangle?</h3>
The perimeter of a rectangle of length l and width w is given as follows:
P = 2(l + w).
The length is an odd integer and the width is <u>5 times the next consecutive odd integer,</u> hence:
l = x, w = 5(x + 2).
The perimeter is of 128 inches, hence:
128 = 2l + 2w
128 = 2x + 10(x + 2)
128 = 2x + 10x + 20
12x = 108
x = 9.
Hence the length is of 9 inches and the width is of 55 inches.
More can be learned about the perimeter of a rectangle at brainly.com/question/10489198
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-4, 1, 2, 3
Step-by-step explanation:
I put them from least to greatest.
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3x(x-1) = 0
x= 1
Step-by-step explanation:
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Step-by-step explanation: divide 6.00 by 14 which gives you around .42857
then you round to the hundredths place which gives you .43
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Step-by-step explanation:
900/9=100
100x9=900
