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<u>Answer:</u> The maximum amount of N-acetyl-p-toluidine that can be prepared is 1.7 grams.
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
Molarity of p-toluidine hydrochloride solution = 0.167 M
Volume of solution = 70. mL
Putting values in above equation, we get:
The chemical equation for the reaction of p-toluidine hydrochloride and acetic anhydride follows:
By Stoichiometry of the reaction:
1 mole of p-toluidine hydrochloride produces 1 mole of N-acetyl-p-toluidine
So, 0.0117 moles of p-toluidine hydrochloride will produce = of N-acetyl-p-toluidine
To calculate the number of moles, we use the equation:
Molar mass of N-acetyl-p-toluidine = 149.2 g/mol
Moles of N-acetyl-p-toluidine = 0.0117 moles
Putting values in equation 1, we get:
Hence, the maximum amount of N-acetyl-p-toluidine that can be prepared is 1.7 grams.
The distance between the scattering planes in the crystal is d = 0.95 A°
<u>Explanation</u>:
The Bragg's equation is given by
2d sinθ = nλ
where,
d is the distance between the scattering planes in the crystal.
θ is the angle of diffraction.
n is the order of diffraction.
λ is the wavelength of X rays.
Given λ = 0.17 nm = 1.7 A°, angle = 62.5
2 d
sin(62.5) = 1
1.7 A°
d = 0.95 A°
The distance between the scattering planes in the crystal is d = 0.95 A°