Answer:
Step-by-step explanation:
<em>See attachment for complete question</em>
Given
Required
Determine the length of VW
Perimeter is calculated as:
This gives:
Substitute values for VW, VY and Perimeter
Collect Like Terms
Divide through by 2
Collect Like Terms
Substitute 6 for x in
Answer:
51
Step-by-step explanation:
See the other answer
Answer:
10 inches.
Step-by-step explanation:
First we need to find what is the bigger dimension of the box, because the relay baton will occupy the box, and the larger dimension of the relay baton (that is, it's length) need to be less or equal than the larger dimension of the box.
The dimensions of the box are: 4 inches, 6 inches and 10 inches.
The larger dimension of the box is 10 inches. So, If we want the relay baton to fit in the box, the maximum length it can have is 10 inches.
Answer:
5.848 in
Step-by-step explanation:
Divide the piece of cardboard into nine equal squares of side z.
The centre square is the base of the cube.
When you cut out the corner squares and fold up the sides, you will have a cube with edge length z.
The cube must have a volume of 200 in³.
V = z³
200 = z³
z = 2 × 2.924
z = 5.848 in
The edge length of the cube is 5.848 in.
B is true.
A dilation creates similar figures. By definition, the proportion of the sides of similar figures is the same. AB/A'B' would be the same as BC/B'C', since the numerator of both comes from the first figure and the denominator of both comes from the second figure.