Answer:
for this question you need to take the 12p and 700 and add then dived by 2x which then gives you your answer
Answer:
B. Systematic
Step-by-step explanation:
<em>Since Quality Control Manager is selecting every 10th soup. This type of Sampling Method is called Systematic Sampling.</em>
Further,
If the whole population is divided into many groups(strata) such that between the group units are heterogeneous and within the group units are homogeneous then units are randomly selected from these groups. This type of sampling is called Stratified Sampling.
If the sampling is done by any criteria then this type of sampling method is called Systematic Sampling. Like observer is taken every 5th unit as a sample.
If the samples from the population are chosen randomly, where each and every unit has an equal chance of selection in a sample. This type of sampling is called Simple Random Sampling.
In Cluster Sampling the population is distributed into a distinct group (clusters) and one or more groups (clusters) are chosen as a sample then it is Cluster Sampling.
If the observers collect the sample as his\her convenience, then this type of sampling method is called Convenience Sampling.
To solve this, just round each number. -1.98≈-2, 5.2≈5, -2.9≈-3, 13.1≈13. The only answer choice which correctly rounds these is A, -2=5(-3)+13
5/6, divide 3/4 to get 0.74 then divide 5/6 to get 0.84 for proof.
Answer:
Expected return for site A = $9.6 million
Expected return for site B = $12.4 million
according to the above results the company should choose SITE B because it has higher Expected return
Step-by-step explanation:
Given;
For site A,
Site A net if successful = $30 million
Success probability = 0.4
Site A loss if not successful= -$4 million
Probability of not successful = 0.6
For site B.
Site B net if successful = $60 million
Success probability = 0.3
Site B loss if not successful= -$8 million
Probability of not successful = 0.7
To estimate the expected return on an event with outcomes X1 and X2 with probabilities p1 and p2
E = X1(p1) + X2(p2)
Substituting for site A
E = 30(0.4) - 4(0.6)
E = $9.6 million
Substituting for site B
E = 60(0.3) - 8(0.7)
E = $12.4 million
Therefore, according to the above results the company should choose site B because it has higher Expected return
