Answer:
a. Zero percent
b. Fifty percent
Explanation:
As it has been mentioned in the question that both man and woman are normally pigmented and each one have an albino parent thus both will be heterozygous and their allelic makeup will be as follows -
Man - Aa
Woman - Aa
After a cross between Aa × Aa we get the following result-
One AA, Two Aa and One aa
It is clear that only the aa type of offsprings will be albino.
Out of 4 there is probability of only one to be albino so out of two there will be 50% probability of being albino.
The probability of both sons to be albino will be zero percent.
Answer: B - People with two copies of the mutated gene have sickle-cell anemia. People with one copy of the mutated gene have both healthy and misshapen red blood cells and are carriers of the disease.
Explanation:
Co-dominance is when both the alleles of a gene in a heterozygote show. In the case of sickle cell anemia (since it is a co-dominant trait) even if the person only has one sickle cell allele, symptoms of sickle cell will still show up in that person. That's why the person in this example has both misshapen and healthy red blood cells.
Answer:
DNA is not neccessarly produced, but is copied from when a parent cell divides into two daughter cells
Explanation:
If you mean where the DNA is stored, it is stored in the nucleus