The solution to the given algebraic equation 1000(7x - 10) = 50(292 + 100x) is; x = 12.3
<h3>How to simplify algebraic equations?</h3>
We want to simplify the algebraic equation;
1000(7x - 10) = 50(292 + 100x)
The first step is to use distributive property of equality to expand the bracket to get;
7000x - 10000 = 14600 + 5000x
7000x - 5000x = 14600 + 10000
2000x = 24600
Use division property of equality to divide both sides by 2000 to get;
x = 24600/2000
x = 12.3
Thus, we can conclude that the solution to the given algebraic equation 1000(7x - 10) = 50(292 + 100x) is; x = 12.3
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Answer:
m∠ADC = 132°
Step-by-step explanation:
From the figure attached,
By applying sine rule in ΔABD,
sin(∠ADB) =
= 0.74231
m∠ADB =
= 47.92°
≈ 48°
m∠ADC + m∠ADB = 180° [Linear pair of angles]
m∠ADC + 48° = 180°
m∠ADC = 180° - 48°
m∠ADC = 132°
Answer:
Step-by-step explanation:
<u>Sides of the picture added margin:</u>
<u>Solution</u>:
- A(margin) = Total area - A(picture)
- (8 + 2x)(5 + 2x) - 5*8 = 30
- 4x² + 10x + 16x + 40 - 40 - 30 = 0
- 4x² + 26x - 30 = 0
- 2x² + 13x - 15 = 0
- x = (-13 + √(13² + 2*4*15))/4
- x = (-13 + 17)/4
- x = 1 cm
Note. The other root is ignored as negative.
Answer:
The answer is given below
Step-by-step explanation:
The loads in the circuit are continuous duty, so the circuit can only loaded to 80% of its current rating.
Calculate 80% current rating of the circuit breaker.
Icb = [ 80/100] (20 A)
= (O.8) (20 A )
= 16 A
Now we assume that the value of supply voltage is 120 V
Now we will calculate current flows via under water light which will be taken as Load 1
<em>Ii = </em>500 W/120 V
= 4.167 A
Current via the circulating pump which will be taken as Load 2 IS 8.5 A
<em>I = </em>load1 + load 2
<em> = 4.167 A + 8.5 A</em>
<em> = 12.67 A</em>
The total current in the circuit obtained which is less than the circuit breaker rating current. Therefore, the power can be operated for both the loads.