Answer:
First, find tan A and tan B.
cosA=35 --> sin2A=1−925=1625 --> cosA=±45
cosA=45 because A is in Quadrant I
tanA=sinAcosA=(45)(53)=43.
sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.
sinB=1213 because B is in Quadrant I
tanB=sinBcosB=(513)(1312)=512
Apply the trig identity:
tan(A−B)=tanA−tanB1−tanA.tanB
tanA−tanB=43−512=1112
(1−tanA.tanB)=1−2036=1636=49
tan(A−B)=(1112)(94)=3316
kamina op bolte
✌ ✌ ✌ ✌
Answer:
14
Step-by-step explanation:
add
2+4a=-10
First, subtract 2 from both sides.
4a=-12
Then divide 4 from both sides.
a=-3
hope it helps!
Prime numbers basically numbers that dont have any numbers that will be multiplied to get to it. So, it would be:
23
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
All the other numbers in between can be divided by something and not become a decimal. Other than 23, it can be divided by anything without becoming a decimal.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
<em>~Hope this helped :)</em>
One solution!
Step-by-step explanation:
If we make a graph of the given equations, the lines will intersect at a point. We know that whenever lines intersect, it means the equations have one solution or a unique solution.