The picture is below of how to separate this into 2 different regions, which you have to because it's not continuous over the whole function. It "breaks" at x = 2. So the way to separate this is to take the integral from x = 0 to x = 2 and then add it to the integral for x = 2 to x = 3. In order to integrate each one of those "parts" of that absolute value function we have to determine the equation for each line that makes up that part.

For the integral from [0, 2], the equation of the line is -3x + 6;

For the integral from [2, 3], the equation of the line is 3x - 6.

We integrate then:

$\int\limits^2_0 {-3x+6} \, dx+\int\limits^3_2 {3x-6} \, dx$ and

$-\frac{3x^2}{2}+6x\left \} {{2} \atop {0}} \right. +\frac{3x^2}{2}-6x\left \} {{3} \atop {2}} \right.$ sorry for the odd representation; that's as good as it gets here!

Using the First Fundamental Theorem of Calculus, we get:

(6 - 0) + (-4.5 - (-6)) = 6 + 1.5 = 7.5

5 0

2 years ago

in the figure given alongside, AB is the diameter of circle with centre O. If <COD=50°, find the size of <CED.

Ksju [112]

Answer:

Step-by-step explanation:

code in parm so the angle o is equal to e

that is a property of the parm

5 0

1 year ago

What's the estimate of 608×8

rusak2 [61]

Answer:

3,200

Step-by-step explanation:

you would have to multiply then estimate wich round it down an dyou get 3,200

3 0

2 years ago