Area of a circle for (360degrees) = pi*(r^2)
Area of part of a circle with angle θ=(θ/360)*(pi*)*(r^2)
<span>(θ/360)*pi*(6^2)=12*pi
</span>solving, <span>θ=(12/36)*360
</span><span>θ=120 degress
</span>
Answer:
Step-by-step explanation:
The sum is the result obtained from adding two or more values together.
The sum of <em>s</em> and <em>t</em> is the result obtained from adding <em>s</em> and <em>t</em> together.
<em>s </em>+<em> t</em>
it's x ≤ 3 :))) I found it out after realizing what you were asking
Answer:
P(Z < 2.37) = 0.9911.
Step-by-step explanation:
We are given that Let z denote a random variable that has a standard normal distribution.
Let Z = a random variable
So, Z ~ Standard Normal(0, 1)
As we know that the standard normal distribution has a mean of 0 and variance equal to 1.
Z = ~ N(0,1)
where, = mean = 0
= standard deviation = 1
Now, the probability that z has a value less than 2.37 is given by = P(Z < 2.37)
P(Z < 2.37) = P(Z < ) = P(Z < 2.37) = 0.9911
The above probability is calculated by looking at the value of x = 2.37 in the z table which has an area of 0.9911.
Surface area is:
6*8=48
12*10=120
8*12=96
6*12=72
48+72+120+96 = 336
The surface area is 336 square km