Answer:
increasing the separation between the plates
Explanation:
The increase in the vacuum/separation between the plates in a parallel plate capacitor connected to a constant potential difference decreases the energy stored in the capacitor. the increase in the separation of the plates of a parallel plate capacitor reduces the capacitance of the capacitor because
Q(charge) = CV V = VOLTAGE , c = capacitance
E = 1/2 eAV^2/ D ( ENERGY STORED )
where D = distance between plates, e = dielectric, A = area of capacitor , V = potential difference
Answer:
Velocity of the electron at the centre of the ring, 
Explanation:
<u>Given:</u>
- Linear charge density of the ring=
- Radius of the ring R=0.2 m
- Distance of point from the centre of the ring=x=0.2 m
Total charge of the ring
Potential due the ring at a distance x from the centre of the rings is given by
The potential difference when the electron moves from x=0.2 m to the centre of the ring is given by
Let
be the change in potential Energy given by
Change in Potential Energy of the electron will be equal to the change in kinetic Energy of the electron
So the electron will be moving with
Answer:
No
Explanation:
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