Answer:
288
Step-by-step explanation:
Hope it helps :>
The number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.
<h3>How to determine the number of ways</h3>
Given the word:
ESTABROK
Then n = 8
p = 6
The formula for permutation without restrictions
P = n! ( n - p + 1)!
P = 8! ( 8 - 6 + 1) !
P = 8! (8 - 7)!
P = 8! (1)!
P = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 × 1
P = 40, 320 ways
Thus, the number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.
Learn more about permutation here:
brainly.com/question/4658834
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Answer:
range of scores on final exam student get B is 90 to 100
Step-by-step explanation:
given data
Psychology 101 score = 66
average of his midterm = between 78 and 90
maximum = 100 points
to find out
range of scores on final exam student get B
solution
we consider here lowest marks need in final = x
so average at two marks should be
equation is
average marks = 0.5 × ( mid term marks + final marks ) .................1
put here value
78 = 0.5 × ( 66 + x )
x = 90
and
90 = 0.5 × ( 66 + x )
x = 114
so range 90 to 114
but maximum marks is 100 so
range of scores on final exam student get B is 90 to 100
the answer is 41 because you cross multiply then divide by 8.5 and get the answer