Consider the first four terms of the sequence below.

Mathematics

1 answer:

tigry1 [53]1 year ago

8 0

Answer:

the answer is C.-1/128......

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Question 1 (Essay Worth 10 points)

Shalnov [3]

✿————✦————✿————✦————✿

The answer is: <u>2(k2−4k)(2c+5)</u>

✿————✦————✿————✦————✿

Step:

* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.

* Factor out the common term 2c+5 by using the distributive property.

* Rewrite the complete factored expression.

✿————✦————✿————✦————✿

6 0

2 years ago

2 d2 + 15d + 23 = 3<br> It’s quadratic formula

DENIUS [597]

Answer:

-15 plus or minus the square root of 65 all over 4 (All over means fraction)

4 0

2 years ago

Drag values to complete each equation.

Alex777 [14]

Answer:

1. A. 1

2. D. $17^9$

Step-by-step explanation:

Properties used:

Power of a Power Property
Product Property
Quotient Property
Zero Exponent Property

1. First, let's deal with the numerator.

$(17^3)^6$ can be turned into $17^1^8$ by using the Power of a Power Property.

And then use the Product Property, $(17^1^8)(17^-^1^0) = 17^8$

So now, our fraction is this: $\frac{17^8}{17^8}$

All number over itself in a fraction is equal to 1. But you can also do this the mathmatic way using the Quotient Property: $\frac{a^m}{a^n} = a^m^-^n$ or $\frac{1}{a^(^n^-^m^)}$ . Which then you plug the numbers in: $\frac{17^8}{17^8} = 17^8^-^8 = 17^0$ . And since we know that in Zero Exponent Property: $a^0 = 1$ , we can see that $17^0 = 1$ . So either way, we get 1.