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2 years ago

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Element X has an average atomic mass of 64.32 amu. If this element consists of only two isotopes, X-64 and X-65, which isotope i

s present in the greater abundance? Explain how you can tell.

1 answer:

PIT_PIT [208]2 years ago

8 0

Answer:X-64 is closer to the atomic mass of 64.32 amu. The one on the periodic table is the isotope most common in nature.

Explanation:

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Question 1 of 6

Juli2301 [7.4K]

Answer:

Option A. 2, 3, 2

Explanation:

We'll begin by balancing the equation. This can be achieved by doing the following:

Fe + Cl2 —> FeCl3

There are 2 atoms of Cl on the left side and 3 atoms on the right side. It can be balance by putting 3 in front of Cl2 and 2 in front of FeCl3 as shown below:

Fe + 3Cl2 —> 2FeCl3

There are 2 atoms of Fe on the right side and 1 atom on the left side. It can be balance by putting 2 in front of Fe as shown below:

2Fe + 3Cl2 —> 2FeCl3

Now the equation is balanced.

The coefficients are : 2, 3, 2

8 0

2 years ago

What is the total number of Ions in N2O3?

aleksandrvk [35]

The total number of lone pairs of electrons in N2O3 is 8.

4 0

1 year ago

Read 2 more answers

2 C2H6 + 7 026 H2O + 4 CO2

Kay [80]

Answer:

Oxygen is limiting reactant

Explanation:

Based on the chemical reaction:

2C2H6 + 7O2 → 6H2O + 4CO2

<em>2 mole of ethane reacts with 7 moles of oxygen</em>

<em />

For a complete reaction of 5.25 moles of ethane are required:

5.25 moles Ethane * (7mol Oxygen / 2mol Ethane) = 18.38 moles of oxygen

As there are just 15.0 moles of oxygen

<h3>Oxygen is limiting reactant</h3>

3 0

2 years ago

Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon monoxide gas, CO?

Ber [7]

Answer: C. The Number of Molecules

Explanation: I just took the test, it's correct.

6 0

2 years ago

The cylinder of aluminum in class was approximately 13mm in circumference and 42mm in length. What would be it's approximate mas

Roman55 [17]

Answer:

Mass, m = 1.51 grams

Explanation:

It is given that,

The circumference of Aluminium cylinder, C = 13 mm = 1.3 cm

Length of the cylinder, h = 4.2 cm

We know that the density of the Aluminium is 2.7 g/cm³

Circumference, C = 2πr

$r=\dfrac{C}{2\pi}\\\\r=\dfrac{1.3}{2\pi}\\\\r=0.206\ cm$

Density is equal to mass per unit volume.

$d=\dfrac{m}{V}$

m is mass of the cylinder

V is the volume of the cylinder

$V=\pi r^2h\\\\V=\dfrac{22}{7}\times0.206^2\times 4.2\\\\V=0.5601\ cm^3$

So,

$m=d\times V\\\\m=2.7\times 0.5601\\\\m=1.51\ g$

So, the mass of the cylinder is 1.51 grams.

5 0

2 years ago