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2 years ago

Which of the following is the result of expanding? 4 8 17 18

Mathematics

2 answers:

Nuetrik [128]2 years ago

8 0

Answer:

Please provide more details of the question

I don't think you've written the whole question correctly

Neporo4naja [7]2 years ago

6 0

Answer:

B. 8

Step-by-step explanation:

edge 2021

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Calculate the perimeter of this figure.Round your answer to the nearest tenth.p=(?)ft 8,10,8.9,4

o-na [289]

Answer:

30.9

Step-by-step explanation:

8 + 10 + 8.9 + 4 = 30.9

5 0

2 years ago

The points plotted below satisfy a polynomial equation. What type of extreme value does the graph have in the part that is visib

bezimeni [28]

Hi!

The graph shows an A) Maximum

A Maximum value appears in a graph when all other values of the polynomial are smaller in value i.e. are under it in an X-Y plot. This is expressed mathematically as:

There is a maximum if for a given x*: f(x*) ≥ f(x) for all x.

In the graph, you can clearly see that there is a value that is higher than all the others, so this value is a Maximum.

3 0

2 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

2 years ago

How do you write 50% as a decimal?

Marina86 [1]

There is an understood decimal behind the 0. move the decimal two places to the left. making it .50. <span />

7 0

2 years ago

Read 2 more answers

You are asked to select a password for a Web site. It must consist of fivelowercase letters and two digits in any order.Howmany

Alika [10]

5 lowercase, so
26 letters
any order, so I gues you can repeat
and 2 digits, 10 digits
so
26^5 times 10^2 or
1188137600 possible passwords

7 0

2 years ago