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2 years ago

Pls help me on this question.

Mathematics

1 answer:

PIT_PIT [208]2 years ago

3 0

Answer:

-1= 1

0= 1

1= 3

2= 5

3= 7

4= 9

5= 11

6= 13

just plug in the numbers for "X"

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Please help with this math

Studentka2010 [4]

Answer:

I believe it’s C

Step-by-step explanation:

let me know if right if am mark brainliest pls

7 0

2 years ago

1/2 or (1/2)² which value is greater

Ket [755]

Answer:

when a expression is squared (²) that means it is multiplyed by itself.

Step-by-step explanation:

(1/2)² = (1/2 x 1/2)

1 squared = 1

2 squared = 4

1/4 is smaller than 1/2. 1/2 is greater than (1/2)²

3 0

2 years ago

5x−y=14 in slope intercept form <br> y=_

frozen [14]

Simple, rewrite this equation, in y=mx+b form.

Move over the 5x, making it look like, -y=-5x+14

Then, just simply divide by the negative one in front of the y.

y=5x-14.

3 0

2 years ago

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Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab

Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

$SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx$

If $f(x)=x^2,$ then

$f'(x)=2x$

and

$b=0\\ \\a=2$

Therefore,

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx$

Apply substitution

$x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du$

Then

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du$

Now

$\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))$

Hence,

$SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}$

3 0

2 years ago

What is 945-89x587÷2

andriy [413]

Answer:-25176.5

Step-by-step explanation:

6 0

2 years ago

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