X² + 1 = 0
=> (x+1)² - 2x = 0
=> x+1 = √(2x)
or x - √(2x) + 1 = 0
Now take y=√x
So, the equation changes to
y² - y√2 + 1 = 0
By quadratic formula, we get:-
y = [√2 ± √(2–4)]/2
or √x = (√2 ± i√2)/2 or (1 ± i)/√2 [by cancelling the √2 in numerator and denominator and ‘i' is a imaginary number with value √(-1)]
or x = [(1 ± i)²]/2
So roots are [(1+i)²]/2 and [(1 - i)²]/2
Thus we got two roots but in complex plane. If you put this values in the formula for formation of quadratic equation, that is x²+(a+b)x - ab where a and b are roots of the equation, you will get the equation
x² + 1 = 0 back again
So it’s x=1 or x=-1
Answer:
candy= 11 popcorn=4
Step-by-step explanation:
11x2=22
4x4=16
16+22=36
Answer:
number 10
dy/dx =(dy/dt).(dt/dx)
now find
dy/dt=4t-1. , dt/dx=1
so : dy/dx=(4t-1).(1)
dy/dx= 4t-1 ,we have x=t-3-----> t=x+3
subtitute at t
dy/dx= 4(x+3)-1=4x+12-1= 4x+11
Answer:
i tried on a calculator and it gave me 211.125