Answer:
1.
a = 112
b = 68
c = 68
2.
a = 127
3.
a=35
b=40
c=35
d=70
4.
a= 30
b=70
c = 30
d=70
e = 130
I'll help you with the rest later
Step-by-step explanation:
a = 112 because of allied angles rule
b and c = 68 because of angles at a point
360-112-112 ÷2
2. a = 127 because of angles on a straight line rule.
180-38-15
3. d= 70, vertically opposite angle
using angles on a straight line, 180 - 70 - 40 ÷ 2
we now have the two angles and because they are vertically opposite a and c = 35
b = 40 because of vertically opposite angles
4. a=30 because 90-70
since a=30, take 90 - 30 to get b, 70
d= 70, vertically opposite angles
e = 130 because a+b+c, vertically opposite angles
So it’s saying that the following set in roster form: (1) N = (x :x is an odd number, 21< × ≤ 35,×€ N)?
It seems to be that the Roster form would do not do anything but the thing is that this listing would give us the output of a set from this problem.
Your answer would be, N = Set of Odd Numbers such that x is greater than 21 and less than or equal to 35 = {23, 25, 27, 29, 31, 33, 35}.
Answer:
-1
Step-by-step explanation:
took the exam on edge
Answer:
360
Step-by-step explanation:
(i think that is a 1 not an L)
21 + 9 equals 30. And 21-9 equals 12. So you would multiply 30*12 which gives you your answer!
<h2>360</h2>
