You're going to divide the mass of chlorine within the compound by the mass of the compound, and then multiply the result by 100 to get the answer
Answer:
See Explanation Below
Explanation:
A) The rate law can only be on the reactant side and you can only determine it after you get the net ionic equation because of spectators cancelling out. So in this case the rate law is k=[CH3Br]^1 [OH-]^1. The powers are there because the rxn is first order.
B) Since the rxn is first order anything you do to it will be the exact same "counter rxn" per say so since you are decreasing the OH- by 5 the rate will decease by 5
C) The rate will increase by 4 since you are doubling both you have to multiply them both.
Answer:
19 °C
Explanation:
Step 1: Given and required data
- Mass of granite (m): 20 g
- Heat absorbed (Q): 300. 2 J
- Specific heat capacity of granite (c): 0.790 J/g.°C
Step 2: Calculate the temperature change (ΔT)
We will use the following expression.
Q = c × m × ΔT
ΔT = Q/c × m
ΔT = 300.2 J/(0.790 J/g.°C) × 20 g = 19 °C
Answer:
B.Bronze is harder than copper, so it retains a cutting edge sharper than that of copper.
Explanation:
The importance of bronze in the history of the human kind can not be only measured in the durability but the help that it provided to our ancestors, the things they were allowed to do once they dicovered how to mold it, and the tools that they produced and made many every day tasks easier for them and the ability of bronze to mantain the cutting edge longer than copper was one of the main reasons why it took its places in the fabrication of many tools.
ans A. 13 to 3
solution:
Total puppies for sale=6
Total puppies left = 2
hence total puppies sold= 6 - 2 = 4
cost of a puppy= $ 104
so cost of 2 puppies = 104 x 4
=416$
Now for kittens:
Total kittens for sale = 12
Total kittens left = 8
hence total kittens sold=12 - 8 =4
cost of a kitten = $24
so cost of 4 kittens= 24x 4=96$
Now ratio of sales of puppies to kittens = 208$/96$
= 13/3 or 13:3 or 13 to 3
I hope this explanation will help you to understand this problem