Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
cuatro no? porque osea tiene q
Answer:
g(x) = x^2 -6x +9
Step-by-step explanation:
A function f(x) translated right h units and up k units will become ...
g(x) = f(x -h) +k
You want the function f(x) = x^2 to be translated right h=3 units, so it will become ...
g(x) = f(x -3) = (x -3)^2
g(x) = x^2 -6x +9
Answer:
p = 7
Step-by-step explanation:
set the expressions = to each other
4(n+7) = 4(n+p)
distribute the 4 on both sides(multiplying the numbers on the inside)
4n+28 = 4n+4p
subtract the 4n from the right and left
28 = 4p
divide by 4
p = 7
From x equals five to nine, the y value changes as follows
+10,+2,+1,+3
Assuming that "average" implies the mean, the sum of all four values is 15. Then divide 15 by the four values added = 15/4 = 3 3/4 or 3.75