Given that f(x)=x^2+3x+6 and g(x)= x-3/2, solve for f(g(x)) when x=1

1 answer:

4 0

If you would like to solve for f(g(x)) when x = 1, you can do this using the following steps:

<span>f(x) = x^2 - 3x + 6
g(x) = x - 3/2

f(g(x)) = f(</span>x - 3/2) = (x - 3/2)^2 - 3 * (x - 3/2) + 6
x = 1
f(g(1)) = f(1 - 3/2) = f(-1/2) = (-1/2)^2 - 3 * (-1/2) + 6 = 1/4 + 3/2 + 6 = 1/4 + 6/4 + 24/4 = 31/4 = 7 3/4

The correct result would be 7 3/4. add me as a friend

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A room has a rectangular floor that is 15 feet by 21 feet. What is the area of the floor in square yards ?

Soloha48 [4]

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Hey There!

Let's solve...

Here it is a rectangular floor with length =21 cm and width =15cm

$area = l \times w \\ = 21 \times 15 \\ = 315 {ft}^{2} \\ \\$

So now We need to convert it to yards square

$315ft^{2} \times \frac{ {1yd}^{2} }{ {9ft}^{2} } \\ \\ = \cancel{315ft^{2}} \: ^{35} \times \frac{ {1yd}^{2} }{ \cancel{9 {ft}^{2} }} \\ \\ = 35 {yd}^{2}$