Question

find the length, width, area, and perimeter of a rectangle where the length is 5 units more than the width and the perimeter is 9 times the width

Answer 1

Step-by-step explanation:

L= W+5

P= 9W

P= 2L+ 2W

9W= 2(W+5) + 2W

9W= 2W +10 +2W

9W = 4W +10

5W = 10

W = 2

L=7

P= 9(2)

P= 18

A= LW

A= 7 x 2

A= 14