Answer:
B
Step-by-step explanation:
600+125+175=900-400(deposit)=500
or
600-125-175-300-200=100+400=500
Brainliest Please :)
Answer:
P(X = x, Y = y) = f(x, y)
Step-by-step explanation:
Let X be a discrete random variable, and suppose that the possible values that it can assume are given by x1, x2, x3, . . . , arranged in some order. Suppose also that these values are assumed with probabilities given by
P(X = xk) = f(xk) k = 1, 2, . . . (1)
It is convenient to introduce the probability function, also referred to as probability distribution, given by
P(X = x) = f(x)
If X and Y are two discrete random variables, we define the joint probability function
of X and Y by
P(X = x, Y = y) = f(x, y)
where f(x, y) ≥ 0
Answer:
90-66=24
Step-by-step explanation:
Answer:
B. c = fλ
Step-by-step explanation:
The given equation is
To solve for c you must multiply both sides of the equation by lambda.
Answer:β=√10 or 3.16 (rounded to 2 decimal places)
Step-by-step explanation:
To find the value of β :
- we will differentiate the y(x) equation twice to get a second order differential equation.
- We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β
y(x)=c1cosβx+c2sinβx
we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.
Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate βx in each case and multiply with the differential of c1cosx and c2sinx respectively.
lastly the differential of sinx= cosx and for cosx = -sinx.
Knowing all these we can proceed to solving the problem.
y=c1cosβx+c2sinβx
y'= β×c1×-sinβx+β×c2×cosβx
y'=-c1βsinβx+c2βcosβx
y''=β×-c1β×cosβx + (β×c2β×-sinβx)
y''= -c1β²cosβx -c2β²sinβx
factorize -β²
y''= -β²(c1cosβx +c2sinβx)
y(x)=c1cosβx+c2sinβx
therefore y'' = -β²y
y''+β²y=0
now we compare this with the second order D.E provided in the question
y''+10y=0
this means that β²y=10y
β²=10
B=√10 or 3.16(2 d.p)
