The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
Answer:
6.4
Step-by-step explanation:
You could use a calculator
Or....
Do 345.6/54 and get 6.4
Answer: 12 inches
Step-by-step explanation:
1. f = g(m1 - m2)/d2
2. f d2 = g(m1 - m2)
3. f d2/g + m1 - m2
4. f d2/g + m2 = m1
5. [Answer] m1 = f d2/g + m2
