Answer:
Both equation represent functions
Step-by-step explanation:
The function is the relation that for each input, there is only one output.
A. Consider the equation
This equation represents the function, because for each input value x, there is exactly one output value y.
To check whether the equation represents a function, you can use vertical line test. If all vertical lines intersect the graph of the function in one point, then the equation represents the function.
When you intersect the graph of the function with vertical lines, there will be only one point of intersection (see blue graph in attached diagram). So this equation represents the function.
B. Consider the equation
This equation represents the function, because for each input value x, there is exactly one output value y.
When you intersect the graph of the function with vertical lines, there will be only one point of intersection (see green graph in attached diagram). So this equation represents the function.
Answer:
Step-by-step explanation:
Let 
be the number of bags with 8 onions and let 
be the number of bags with 3 onions. We have the following system of equations:
Subtracting from both sides of the first equation, we get 
. Substitute this into the second equation:
Therefore, the number of 8-onion bags is:
Thus, the chef got 4 8-onion bags and 3 3-onion bags.
Answer:
The measure of an interior angle of a regular 15-gon is 120°.
Step-by-step explanation:
We need to determine the measure of the size of an interior angle of a regular 15-gon having 15 sides.
Thus,
The number of sides n = 15
Hence,
Using the formula to determine the measure of an interior angle of a regular 15-gon is given by
(n - 2) × 180° = n × interior angle
substitute n = 15
(15 - 2) × 180 = 15 × interior angle
13 × 180 = 15 × interior angle
Interior angle = (10 × 180) / 15
= 1800 / 15
= 120°
Therefore, the measure of an interior angle of a regular 15-gon is 120°.
Answer:
FALSE
Step-by-step explanation:
<E in ∆AED ≅ <E in ∆CEB.
Both are 90°.
Side ED ≅ Side EB
Side AD ≅ Side CB.
Thus, two sides (ED and AD) and a non-included angle (<E) of ∆AED are congruent to corresponding two sides (EB and CB) and a non-included angle (<E) of ∆CEB. Therefore, by A-S-S Congruence Theorem, both triangles are congruent to each other not by SSS.
