Rationalizing is just simpllifying, so the simplified value has the same value as the original expression.
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Hope I’m not as late but the cost per topping is 80 cents.
Answer:
15.50h + 50 > 400
Step-by-step explanation:
Given;
Weekly salary = $50 per week
Additional pay = $15.50 per hour
The variable h represent the number of hours worked per week
The total amount earn per week is;
Weekly salary + total additional pay per week
50 + 15.50h
To earn more than $400 this week, the total amount earned in a week must be greater than 400;
15.50h + 50 > 400
Solving the equation we have;
15.50h > 400-50
h > (400-50)/15.50
h > 22.58 hours per week.
Answer: 40
Step-by-step explanation: Multiply by the reciprocal (flip the fraction 1/4), and the new equation is 10*4, which is 40
