Answer:
Midpoint (x , y) of two points is
( x1 + y1/2 , x2 + y2/2)
Midpoint of KL is M ( -8 , 1)
Let the coordinates of L be ( a , b)
From the above definition
Midpoint between K(-6 , 5) and
L ( a ,b) is
(-8 , 1) = ( -6+a/2 , 5+b/2)
Comparing first point with - 8
- 8 = -6 + a /2
Multiply through by 2
We get
-16 = - 6 + a
a = -16+6
a = - 10
Comparing the second point with 1
1 = 5+b/2
Multiply through by 2
2 = 5 + b
b = 2 - 5
b = -3
Therefore a = -10 and b = - 3
Hence the coordinates of
L is ( -10 , - 3)
Hope this helps
(2x-1)(x+4)=0
Step-by-step explanation:
A random zero property of multiplication is taken to find the solution
(2x-1)(x+4)=0
consider a=2x-1 and b=x-4 a.b=0
either a or b or both must be 0
equating both the equations
2x-1=0 or x=4=0 x-4=0
2x-1=0 x=4
2x=1
x=1/2
substitute the values of x in the main equation
[2(1/2)-1][(1/2)+4]=0
Answer:
see explanation
Step-by-step explanation:
Differentiate using the product rule
Given y = f(x)g(x), then
= f(x). g'(x) + g(x). f'(x)
here f(x) = ⇒ f'(x) =
g(x) = cosx ⇒ g'(x) = - sinx
Hence
= (- sinx) + cosx
= cosx - sinx
Answer:
0.207
Step-by-step explanation: MARK ME BRAINless
Add 1/3 on both sides
a= 1