.............................................your answer is 16
Answer:
P( top two horses are predicted incorrectly in incorrect order)
=
Step-by-step explanation:
In the horse race the outcome can be predicted in 5! = 120 ways.
Now suppose the top two horses were predicted incorrectly in incorrect order. Now, the top horse can be predicted incorrectly in 4 ways.
Suppose the top horse was predicted to be in k-th position where k = 2, 3 ,4,5
so the second horse can be predicted to be in place from 1 to (k - 1)
So, the top two horses can be predicted incorrectly in incorrect order
in = 10 ways
and for each prediction of the two the remaining horses may be predicted in 3! = 6 ways.
Hence ,
P( top two horses are predicted incorrectly in incorrect order)
=
=
60x - 12 = 14x^2 + 14x
Subtract 60x & Combine
-12 = 14x^2+14x-60x
-12= 14x^2-46x
Add 12
0= 14x^2-46x-14