<span>The correct answer for this question is that Alice Correa will have spent $6.07 on the cloth overall. This can be worked out through first considering what 5% of the original price will be, so $5.79 / 100 = 0.0579 x 5 = $0.28, so $5.79 + $0.28 = $6.07</span>
The first reaction represented is a decomposition reaction due to the fact the bonded pair are being split apart.
The second equation is a single displacement because the B and C have switched places, which is the only change making it a single displacement. If there had been another bond and A had also moved, it would be double.
Answer:
√185 or 13.60 units to the nearest hundredth.
Step-by-step explanation:
For the points (x1,y1) and (x2,y2) the length between the points is given by:
L = √ [ (x2-x1)^2 + (y2-y1)^]
So here we have:
Length of AB √ [ (7- - 4)^2 + (-2 - 6)^2]
= √ (121 + 64)
= √185.
If you put brackets around (2+1), your method of working is:
1) 15-4*(2+1)=3
2) 15-4*3=3
3) 15-12=3
You don't need any more brackets, as the BIDMAS (brackets, Indices, division, multiplication, addition, subtraction) rule does the rest of the job for you.
The answer is therefore: 15-4*(2+1)=3
Given :
On the first day of ticket sales the school sold 10 senior tickets and 1 child ticket for a total of $85 .
The school took in $75 on the second day by selling 5 senior citizens tickets and 7 child tickets.
To Find :
The price of a senior ticket and the price of a child ticket.
Solution :
Let, price of senior ticket and child ticket is x and y respectively.
Mathematical equation of condition 1 :
10x + y = 85 ...1)
Mathematical equation of condition 2 :
5x + 7y = 75 ...2)
Solving equation 1 and 2, we get :
2(2) - (1) :
2( 5x + 7y - 75 ) - ( 10x +y - 85 ) = 0
10x + 14y - 150 - 10x - y + 85 = 0
13y = 65
y = 5
10x - 5 = 85
x = 8
Therefore, price of a senior ticket and the price of a child ticket $8 and $5.
Hence, this is the required solution.