Ask question

Ask question

All categories

2 years ago

6

Please answer. I will mark Brainliest

1 answer:

den301095 [7]2 years ago

4 0

Statement: 1) Triangle ABC
2) 2x 3)x=52

Reason: I’m not sure but probably addition

You might be interested in

Find the smallest positive integer k such that 3240/k is a square number

sashaice [31]

Answer:

10

Step-by-step explanation:

First, factorize the number 3,240:

$3,240=2\cdot 1,620=2\cdot 2\cdot 810=2\cdot 2\cdot 2\cdot 405=2\cdot 2\cdot 2\cdot 2\cdot 5\cdot 81=2^3\cdot 5\cdot 9^2$

So,

$3,240=2^2 \cdot 2\cdot 5\cdot 9^2=18^2\cdot 10$

Now consider the fraction

$\dfrac{3,240}{k}=\dfrac{18^2\cdot 10}{k}$

If k = 10, then

$\dfrac{3,240}{k}=\dfrac{18^2\cdot 10}{10}=18^2$

is a square number.

For all k < 10, the fraction tex]\dfrac{3,240}{k}[/tex] is not a square number (this follows from factorization).

Or you can simply check the values of the fraction for all k < 10:

k = 1, $\dfrac{3,240}{1}=3,240$ is not a square number;
k = 2, $\dfrac{3,240}{2}=1,620$ is not a square number;
k = 3, $\dfrac{3,240}{3}=1,080$ is not a square number;
k = 4, $\dfrac{3,240}{4}=810$ is not a square number;
k = 5, $\dfrac{3,240}{5}=648$ is not a square number;
k = 6, $\dfrac{3,240}{6}=540$ is not a square number;
k = 7, $\dfrac{3,240}{7}$ is not a square number;
k = 8, $\dfrac{3,240}{8}=405$ is not a square number;
k = 9, $\dfrac{3,240}{9}=360$ is not a square number.

5 0

2 years ago

Do you have to line up the decimals when multiplying

Readme [11.4K]

No, you do not have to line up the decimals.

5 0

2 years ago

If f(x)=4x+3 and g(x)=x^2-3 then f(g(2))

grandymaker [24]

Answer:

<em>f(g(2))=7</em>

Step-by-step explanation:

<u>The Composite Function</u>

Given f(x) and g(x) as real functions, the composite function $(f\circ g)(x)$ is defined as:

$(f\circ g)(x)=f(g(x))$

It can be found by substituting g into f.

The given functions are:

$f(x)=4x+3$

$g(x)=x^2-3$

It's required to find f( g( 2 ) )

Find g(2):

$g(2)=2^2-3$

Operating:

$g(2)=4-3 =1$

g(2)=1

Now find f(1):

$f(1)=4(1)+3$

$f(1)=4+3 =7$

Thus:

f( g( 2 ) )=7

4 0

2 years ago

Sin2A+sin2B+sin2C÷4cosA/2.cosB/2.cosC/2

Mrrafil [7]

The answer is c2 have a good day !!!! Bc you add all the numbers up and you will get it

3 0

1 year ago

Evaluate the expreesion 41

irakobra [83]

Answer:

i'm pretty sure 41 is not an expression

Step-by-step explanation:

7 0

2 years ago