Answer:
x = -5
, y = 1
Step-by-step explanation:
Solve the following system:
{3 x + y = -14 | (equation 1)
-2 x - y = 9 | (equation 2)
Add 2/3 × (equation 1) to equation 2:
{3 x + y = -14 | (equation 1)
0 x - y/3 = (-1)/3 | (equation 2)
Multiply equation 2 by -3:
{3 x + y = -14 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract equation 2 from equation 1:
{3 x+0 y = -15 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 3:
{x+0 y = -5 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer: {x = -5
, y = 1
I'm not good with any math that is above per algebra sorry.
Answer:
may be its -6 units
Step-by-step explanation:
because if you count the number it will be-6
Answer:
The phrasing of the question is weird, but the mass should not change. The scale may read higher for a moment, but once the mass is brought up to the same velocity of the elevator, it should settle back to 100.
5. You have correctly shown the decimal equivalents of the numbers in selection C. Those are in order. The decimal equivalents for selection D would be
... -1.33, -2.00, -1.00, -0.08, -0.07
The first of these is greater than the second of these, so this list is not in order. The correct choice is D.
6. √169 = 13, the only rational number in the lot. The correct choice is C.
8. All the numbers except the ones with radicals are rational numbers, so the appropriate choice is the one that lists the radicals only: G.
9. You have correctly plotted the points. When you connect them to make a geometric figure, you get a triangle that is 6 units high and 6 units wide. Its area will be half that of a square that is 6×6, so is 18 square units.
_____
The formula for the area of a triangle is
... A = (1/2)bh
where b is the base length of the triangle (6 units), and h is the height (6 units). Filling in the numbers you have, this is
... A = (1/2)·6·6 = 18 . . . . square units.
When you have a plot like this on a graph, it is usually pretty easy to see that the triangle area is half the area of a rectangle (or square) with the same height and width.
