Cz I secretly enter this site
Non of my family knows
Cz they are over protective lol
Only a cousin know
That's why l can't pay to comment
It's sad life bro
Answer: The garden has dimensions 30 ft wide X 60 ft long
Step-by-step explanation:
Denote by W the width of the garden and L the length of the garden (longer side) as in the figure attached. The red sides on the figure represent the parts of the garden that require fencing.
L is also the measure of a vertical side of the garden, because a rectangle consists only of vertical and horizontal sides.
We know that the barn is parallel to the longer (vertical) side, so only one of the vertical sides L of the rectangle needs fencing. The other two parts correspond to the horizontal sides of the rectangle so they require 2W feet of fencing. Altogether, the 120 ft of fencing enclose the L+2W ft of the fence, then 120=L+2W. Because the longer side is twice the width, we have that L=2W, so 120=2W+2W=4W. From here, W=30 ft and L=2(30)= 60ft.
If secant of theta =
<span>
<span>
<span>
1.0416666667
</span>
</span>
</span>
then
theta = 16.26 Degrees
cotangent of theta = 3.4286
Answer:
Step-by-step explanation:
The sequence above is geometric progression.
The nth term of such sequence is given by;
Tn = ar∧(n-1),
Where a⇒first term and
r⇒common ratio
So, 1st term = 5×1.25∧(1-1) = 5×1.25∧0 =5
2nd term = 5×1.25∧(2-1) = 5×1.25 = 6.25
3rd term = 5×1.25∧(3-1) = 5×1.25² = 7.8125
4th term = 5×1.25∧(4-1) =5×1.25³ = 9.765625
5th term = 5×1.25∧(5-1) = 5×1.25∧4 = 12.20703125
6th term = 5×1.25∧(6-1) = 5×1.25∧5 = 15.25878909