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1 year ago

how many bricks each 22 cm long and 15 CM broad will be required to pave a court 30 metre long and 22 wide

Mathematics

2 answers:

____ [38]1 year ago

6 0

Answer:

20,000 bricks

Step-by-step explanation:

length of brick(L)=22cm

breadth of brick(B)=15cm

now,

area of brick(A)=L×B

=22×15s.q.cm

=0.033s.q.m

again,

length of court(l)=30m

breadth of court(b)=22m

now,

area of court(a)=l×b

=30×22s.q.m

=660s.q.m

lastly,

no.of required brick=area of court/area of

brick

=600 s.q.m/0.033s.q.m

=20,000bricks

Artyom0805 [142]1 year ago

3 0

Answer:

BBBBBBBBBBBBBBBBBBBB

Step-by-step explanation:

CAUSE I SAID SO

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6 0

2 years ago

Write the equation of a line that is perpendicular to x=3x=3x, equals, 3 and that passes through the point (0,-4)(0,−4)left pare

leva [86]

Answer: $x+3y=12$

Step-by-step explanation:

Slope of two lines that are perpendicular to each other is 1.

If one line is $y=3x$ , then its slope = 3 [by comparing to the linear equation y= mx+c, here m=3]

Let n be the slope of the required line, then

$n\times3=-1\\\\\rightarrow\ n=\dfrac{-1}{3}$

Equation of line with slope n and passers through (a,b) is

$(y-b)=n(x-a)$

Equation of line with slope n= $\dfrac{-1}{3}$ and passes through point ( 0,-4) :

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8 0

2 years ago

how many bricks each 22 cm long and 15 CM broad will be required to pave a court 30 metre long and 22 wide​

how many bricks each 22 cm long and 15 CM broad will be required to pave a court 30 metre long and 22 wide