What is the length of the shadow cast on the vertical screen by your 10.0 cm hand if it is held at an angle of θ=30.0∘ above hor
1 answer:
Answer:
The length is
Explanation:
From the question we are told that
The length of the hand is
The angle at the hand is held is
Generally resolving the length the length of the hand to it vertical component we obtain that the length of the shadow on the vertical wall is mathematically evaluated as
substituting values
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Answer:
48.16 %
Explanation:
coefficient of restitution = 0.72
let the incoming speed be = u
let the outgoing speed be = v
kinetic energy = 0.5 x mass x
- incoming kinetic energy = 0.5 x m x
- coefficient of restitution =
0.72 =
v = 0.72u
therefore the outgoing kinetic energy = 0.5 x m x
outgoing kinetic energy = 0.5 x m x
outgoing kinetic energy = 0.5184 (0.5 x m x )
recall that 0.5 x m x is our incoming kinetic energy, therefore
outgoing kinetic energy = 0.5184 x (incoming kinetic energy)
from the above we can see that the outgoing kinetic energy is 51.84 % of the incoming kinetic energy.
The energy lost would be 100 - 51.84 = 48.16 %
Answer:
Pressure,
Explanation:
It is given that,
Combined mass of the man and the chair, m = 95 kg
Radius of the leg of chair, r = 0.5 cm = 0.005 m
A large man sits on a four-legged chair with his feet off the floor. The force acting per unit area is called the pressure exerted.
Area of 4 legs, A = 4 A
So, the pressure each leg exert on the floor is . Hence, this is the required solution.
Answer:
Time period for Simple pendulum,
Explanation:
The Simple Pendulum
Consider a small bob of mass is tied to extensible string of length
that is fixed to rigid support. The bob is oscillating in the plane about verticle.
Let is the angle made by string with vertical during oscillation.
Vertical component of the force on bob,
Negative sign shows that its opposing the motion of bob.
Taking as very small angle then,
Let is the displacement made by bob from its mean position ,
then,
so, ........(1)
Since, pendulum is in hormonic motion,
as we know,
where is the constant and
.........(2)
From equation (1) and (2)
Since,