Question :What's oxidation?

What is the concentration of a solution that is 0.25 moles of HCL added to 3.00L of water?

Lina20 [59]

Answer: 0.08 M

Explanation:

$\text{molarity}=\frac{\text{moles of solute}}{\text{liters of solution}}\\\\\text{molarity}=\frac{0.25}{3.00}\\\\\text{molarity}=\boxed{0.08 \text{ M}}$

3 0

1 year ago

Which statement describes how chemical formulas, such as H2O, represent compounds

grandymaker [24]

Answer:

Which statements describe how chemical formulas, such as H2O, represent compounds? ... They show the elements that make up a compound. They show the types of atoms that make up a molecule. They show the number of each type of atom in a molecule.

5 0

2 years ago

Read 2 more answers

What is the concentration of FeCl3 in a solution prepared by dissolving 10.0 g of FeCl3 in enough water to make 275 mL of soluti

puteri [66]

Answer: The concentartion of solution will be 0.224 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute = $\frac{\text{Given mass}}{\text{Molar mass}}=\frac{10.0g}{162.2g/mol}=0.0616moles$

${V_s}$ = volume of solution in ml = 275 ml

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{0.0616\times 1000}{275ml}=0.224mole/L$

Therefore, the concentration of solution will be 0.224 M

7 0

3 years ago

What is the total number of molecules in 11.2 liters of N2 gas at STP

scoray [572]

Molar volume at STP = 22,4 L

1 mole -------------- 22,4 L
x mole -------------- 11,2 L

x = 11,2 / 22,4

x = 0,5 moles of N2

1 mole --------------- 6,02.10²³ molecules
0,5 moles ------------ y molecules

y = 0,5 . 6,02.10²³

y = 3,01.10²³ molecules

7 0

2 years ago

What is the composition, in atom percent, of an alloy that contains a) 44.5 lbm of silver, b) 84.7 lbm of gold, and c) 7.3 lbm o

Fed [463]

Answer: The atom percent of silver, gold and copper in the alloy is 43.08 %, 44.93 % and 11.99 % respectively

Explanation:

To convert the given masses into grams, we use the conversion factor:

1 lb = 453.6 grams

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

To calculate the atom percent of substance in sample, we use the equation:

$\%\text{ composition of substance}=\frac{\text{Moles of substance}\times N_A}{\text{Total moles of sample}\times N_A}\times 100$ ......(2)

where,

$N_A$ = Avogadro's number

Moles of Silver:

Mass of silver = 44.5 lb = 20185.2 grams

We know that:

Molar mass of silver = 107.87 g/mol

Putting values in equation 1, we get:

$\text{Moles of silver}=\frac{20185.2g}{107.87g/mol}=187.12mol$

Moles of Gold:

Mass of gold = 84.7 lb = 38419.9 grams

We know that:

Molar mass of gold = 196.97 g/mol

Putting values in equation 1, we get:

$\text{Moles of gold}=\frac{38419.9g}{196.97g/mol}=195.05mol$

Moles of Copper:

Mass of copper = 7.3 lb = 3311.3 grams

We know that:

Molar mass of copper = 63.55 g/mol

Putting values in equation 1, we get:

$\text{Moles of copper}=\frac{3311.3g}{63.55g/mol}=52.10mol$

Total moles of the sample =

For Silver:

Moles of silver = 187.12 moles

Total moles = [187.12 + 195.05 + 52.10] = 434.27 moles

Putting values in equation 2, we get:

$\%\text{ composition of silver}=\frac{187.12\times N_A}{434.27\times N_A}\times 100\\\\\%\text{ composition of silver}=43.08\%$

For Gold:

Moles of gold = 195.05 moles

Total moles = [187.12 + 195.05 + 52.10] = 434.27 moles

Putting values in equation 2, we get:

$\%\text{ composition of gold}=\frac{195.05\times N_A}{434.27\times N_A}\times 100\\\\\%\text{ composition of gold}=44.93\%$

For Copper:

Moles of copper = 52.10 moles

Total moles = [187.12 + 195.05 + 52.10] = 434.27 moles

Putting values in equation 2, we get:

$\%\text{ composition of copper}=\frac{52.10\times N_A}{434.27\times N_A}\times 100\\\\\%\text{ composition of copper}=11.99\%$

Hence, the atom percent of silver, gold and copper in the alloy is 43.08 %, 44.93 % and 11.99 % respectively

3 0

2 years ago

Question :What's oxidation?​

Question :What's oxidation?