D is halfway between A and B
so the coordinates of D are (2,2)
E is halfway between A and C so the coordinates of E are (-1,1)
now you need to find the gradient/slope of DE and BC using the formula:
<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>D</u><u>E</u><u>:</u><u> </u></h3>
SUB IN COORDINATES OF D AND E
therefore the gradient of DE is 1/3.
<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>B</u><u>C</u><u>:</u></h3>
<em>S</em><em>U</em><em>B</em><em> </em><em>I</em><em>N</em><em> </em><em>C</em><em>O</em><em>O</em><em>R</em><em>D</em><em>I</em><em>N</em><em>A</em><em>T</em><em>E</em><em>S</em><em> </em><em>O</em><em>F</em><em> </em><em>B</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>C</em>
<em></em>
therefore the gradient of BC is -2/-6 which simplifies to 1/3.
<h3>
therefore, BC and DE are parallel as they both have a gradient/slope of 1/3 and parallel lines have the same gradient</h3>
Simplify them until they can be simplified no more, then compare both sides.
Your sequence
-8, 16/3, -32/9, 64/27
is a geometric sequence with first term -8 and common ratio
(16/3)/(-8) = (-32/9)/(16/3) = -2/3
The general term an of a geometric sequence with first term a1 and ratio r is given by
an = a1·r^(n-1)
For your sequence, this is
an = -8·(-2/3)^(n-1)
Since there is a negative correlation, evident by the negative slope of the equation of the line given to be -0.5, if we take t as 0, we get an equation of,
s = 3.6
This means that if a student does not watch television, he or she spends a maximum of 3.6 hours studying.
Answer:
Step-by-step explanation:
I think you are just asking for the decimal answers.
3/20 = 0.15
9/50 = 0.18
38/200 = 0.19