Answer:
Step-by-step explanation:
From the question attached,
Given:
RT and PQ intersect at a point S.
RS = PS and ST = SQ
To prove :
RT = PQ
Statements Reasons
1). RS = PS and ST = SQ 1). Given
2). RS + ST = PS + SQ 2). Addition property
3). RS + ST = RT ; PS + SQ = PQ 3). Pair of line segments
4). RT = PQ 4). Substitution property
Answer:
x=-2/3
Step-by-step explanation:
f(x)=9×2/3x+4
0=9×2/3x+4(substitute f (x) =0)
0=9×2/3x+4
0=3×2x+4
0=6x+4
-6x=4( move the variable to left side and change the sign)
Divide both sides.. x=-2/3
Let’s say (5, 3) is Point A, (5, -4) is Point B, and (8, 3) is Point C. If reflected into the y axis, you would simply just make the x signs the opposite of what they already are. Therefore Point A being (-5, 3), Point B being (-5, 4), and Point C being (-8, 3).
Let x be the blank number
x 1/2= 422/2
Cross multiply
x(1)*(2) = 422*2
2x = 844
Divide both sides by 2
2x/2 = 844/2
x = 422
I hope that's help !
