2 years ago

The complex solutions of which equation have a real component of 4?

Mathematics

2 answers:

Tatiana [17]2 years ago

7 0

A step by step dhjajwbs

velikii [3]2 years ago

4 0

Answer:

Step-by-step explanation:

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No 1/5 = 1/5 5/5 = 1 and 5/1= 5

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Solve for x:* 8 – 2(3x + 5) = 0

IRINA_888 [86]

8-2(3x+5)=0
8(-6x-10)=0
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What is the frequency of the function y = -5cos6x? a. -5/6 b. 1/6 c. 5 d. 6

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What is the fourth term in the binomial expansion of (2x – y) 7?

nata0808 [166]

Answer:

$(7C4) (2x)^4 (-y)^{7-4}$

And replacing we got:

$35 (2^4) x^4 (-y)^{-3}$

And then the final term would be:

$-560 x^4 y^3$

Step-by-step explanation:

For this case we have the following expression:

$(2x-y)^7$

And we can use the binomial theorem given by:

$(x+y)^n =\sum_{k=0}^n (nCk) x^k y^{n-k}$

And for this case we want to find the fourth term and using the formula we have:

$(7C4) (2x)^4 (-y)^{7-4}$

And replacing we got:

$35 (2^4) x^4 (-y)^{-3}$

And then the final term would be:

$-560 x^4 y^3$

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4(-9x + 1) = Answer?

faltersainse [42]

Answer:

−36+4

Step-by-step explanation:

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