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2 years ago

Find the median of each set of data. 12, 8, 6, 4, 10, 1 7 6, 3, 5, 11, 2, 9, 5, 0 5 30, 16, 49, 25

Mathematics

1 answer:

professor190 [17]2 years ago

4 0

Answer:

first 7 then 5 and 27.5

Step-by-step explanation:

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PLEASE HELP!!!! attached photo

alisha [4.7K]

Answer:

(-1, -2.5)

Step-by-step explanation:

The midpoint formula is just basicallyadding both of the x values and then dividing the sum of them by 2, after that you will be adding both y values and then dividing them by 2, then you will get the midpoint x and y coordinate values. You can look up midpoint formula on google to see how it's actually written. You have to make sure to add correctly when you are using the negative numbers, because they can actually turn the equations into subtraction. Keep in mind, it can beconfusing sometimes when you are working with positive and negative numbers together. So make sure to just double check your work and also to make sure you added correctly.

Brainliest please, I need a few more :D

8 0

2 years ago

Find the measure of an angle between 0 and 360 coterminal with -323

Roman55 [17]

I hope this helps
372° - 360° = 12°

7 0

2 years ago

Evaluate each expression when a= - 4 and b= 3 ab

Andrews [41]

Answer:

-12

Step-by-step explanation:

Step 1: Substitute

ab -> -4 for a and 3 for b

(-4) * (3)

-12

Answer: -12

6 0

2 years ago

If John drove 210 miles in 3 hours, how far will he have driven in 4.5 hours?

VashaNatasha [74]

Answer:

3hours and 15 mins

Step-by-step explanation:

210 divied by 3=70

70=per hour

4 hours=280

70 divied by 2= 35

.5=35

280+35=315

315 miles in 4.5 hours

3 0

2 years ago

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

e) $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

2 years ago