Answer:
2.28% probability that a person selected at random will have an IQ of 110 or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a person selected at random will have an IQ of 110 or higher?
This is 1 subtracted by the pvalue of Z when X = 110. So
has a pvalue of 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or higher
To change a decimal to a fraction you need to first place the decimal over 1. Next, for each number behind the decimal, you will multiply by a multiple of 10. Since there are 2 numbers behind the decimal, it's 100. Therefore,
92.96 x 100 = 9296
1 x 100= 100
Your new fraction is 9296/100. Now we simplify it. I'm going by 2's so it may take a bit.
Simplifying it twice by 2's your answer would be:
2324/25
Answer:
1 9/16
Step-by-step explanation:
F(1/4) means u plug in 1/4 for x
so the equation would be
f(1/4)=1/4^2+2 1/4 + 1
f(1/4)=1/16+1/2+1
f(1/4)= 9/16 +1
f(1/4)= 1 9/16
its not nine teen its one and 9 over 16 just clarification
Answer: 24 C is your answer
Step-by-step explanation: