Answer:
12.5cm
Step-by-step explanation:
This triangle is either isosceles or equilateral, we already know two sides.
the other side of the triangle is also 5 cm long because it is also the radius of the shape
the format for finding a right angle triangle like this one is base x height / 2
5 x 5 = 25
25/2 = 12.5
12.5 rounded is 13 because the decimal number is 5 and 5 or higher means we need to round up.
hopefully this helped
-cheesetoasty
Answer:
The graph in the attached figure
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form or
In a proportional relationship the constant of proportionality k is equal to the slope m of the line <u><em>and the line passes through the origin</em></u>
In this problem the given line represent a proportional relationship, because passes through the origin
we have
---> the constant of proportionality k is equal to the slope
substitute
The linear equation is
To draw a line we need two points
we have (0,0)
To find the other point
assume x=3 and substitute in the equation to solve for y
so
The other point is (3,4)
using a graphing tool
Plot the points (0,0) and (3,4)
To graph the line join the points
see the attached figure
Answer:
4 14/25
Step-by-step explanation:
4.56 = 4 56/100 = 4 14/25
The moon takes.exactly one month. did that help?
The distance (d) between two points (x1,y1) and (x2,y2) is given by the formula
d = √ ((X2-X1)2+(Y2-Y1)2)
d = √ (-400--800)2+(300-200)2
d = √ ((400)2+(100)2)
d = √ (160000+10000)
d = √ 170000
The distance between the points is 412.310562561766
The midpoint of two points is given by the formula
Midpoint= ((X1+X2)/2,(Y1+Y2)/2)
Find the x value of the midpoint
Xm=(X1+X2)/2
Xm=(-800+-400)/2=-600
Find the Y value of the midpoint
Ym=(Y1+Y2)/2
Ym=(200+300)/2=250
The midpoint is: (-600,250)
Graphing the two points, midpoint and distance
P1 (-800,200)
P2 (-400,300)
Midpoint (-600,250)
The length of the black line is the distance between the points (412.310562561766)