We learned that We are in the disk of the Galaxy, about 5/8 of the way from the center.
<h3>What is the work of Harlow Shapley?</h3>
Shapley, who was headquartered in Boulder, Colorado, used Cepheid variable stars to estimate the size of the Milky Way Galaxy and its position relative to the Sun. In 1953, he published his "liquid water belt" theory, today known as the concept of a livable zone.
There are many stars, grains of dust, and gas in the Milky Way. It is known as a spiral galaxy because, from the top or bottom, it would appear to be whirling like a pinwheel. About 25,000 light-years from the galaxy's nucleus, the Sun is situated on one of the spiral arms.
Approximately 5/8 of the way from the galaxy's nucleus, we are in the disc. William Herschel believed that the Sun and Earth were about in the middle of the vast cluster of stars known as the Milky Way.
To learn more about Harlow Shapley's original estimate go to - brainly.com/question/28145909
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It depends on your weight, your hieght, and how fast you are falling
The x and y components of the velocity vector is 17.32 m/s and 10 m/s respectively.
<h3>
What is the x - component of the velocity?</h3>
The x-component of the ball's velocity is the velocity of the ball in the horizontal direction or x-axis.
The velocity of the ball in x-direction is calculated as follows;
Vx = V cosθ
where;
- Vx is the horizontal velocity of the ball
- V is the speed of the ball
- θ is the angle of inclination of the speed
Vx = (20 m/s) x (cos 30)
Vx = 17.32 m/s
The velocity of the ball in y-direction is calculated as follows;
Vy = V sinθ
where;
- Vy is the vertical velocity of the ball
- V is the speed of the ball
- θ is the angle of inclination of the speed
Vy = 20 m/s x sin(30)
Vy = 10 m/s
Learn more about x and y components of velocity here: brainly.com/question/18090230
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15 km 30 divided by 4 is 7.5 km in 30 min times that by 2 the answer is 15
Answer:
Acceleration a ≤ 3 m/s^2
the greatest acceleration that the truck can have without losing its load is 3 m/s^2
Explanation:
For the truck to accelerate without losing its load.
Acceleration force of truck must be less than or equal to the maximum friction force between the truck bed and the load.
Fa ≤ F(friction)
But;
Fa = mass × acceleration
Fa = ma
ma ≤ F(friction)
a ≤ (F(friction))/m ......1
Given;
Fa = mass × acceleration
Fa = ma
mass m = 800 kg
F(friction) = 2400 N
Substituting the given values into equation 1;
a ≤ F(friction)/m
a ≤ 2400N/800kg
a ≤ 3 m/s^2
the greatest acceleration that the truck can have without losing its load is 3 m/s^2