Answer:
Step-by-step explanation:
This is a recurring decimal.
Let x = 4.666666... ⇒ (1)
10x = 46.66666... ⇒ (2)
Subtract equation (1) from equation (2)
10x = 46.66666..
-<u> x = 4.666666... </u>
<u> 9x = 42.0000.....</u>
<u />
9x = 42
x = 42/9
= 14/3
=
Given:
It is given that,
PQ ⊥ PS and
∠QPR = 7x-9
∠RPS = 4x+22
To find the value of ∠QPR.
Formula
As per the given problem PR lies between PQ and PS,
So,
∠QPR+∠RPS = 90°
Now,
Putting the values of ∠RPS and ∠QPR we get,
or,
or,
or,
or,
Substituting the value of in ∠QPR we get,
∠QPR =
or, ∠QPR =
Hence,
The value of ∠QPR is 40°.
