(0, 5) is the minimum value.
Find the axis of symmetry by plugging the respective variables into -b/2a
-5/2(0) = 0
There is no b-value in our equation, or rather, the value of b is 0. To see this, y = 2x^2 + 5 can be written as
y = 2x^2 + 0x + 5
We plug 0 into f(x), establishing every x-value as 0.
f(0) = 2(0)^2 + 5
f(0) = 0 + 5
f(0) = 5
5 is now your vertex’s y-value. Plot the two values together.
(0, 5)
We know that this is a minimum because the leading coefficient is positive, meaning the the graph’s parabola will open down.
Answer:no
the answer is c
Step-by-step explanation:
Answer:
Step-by-step explanation:
An intercept is where the line hits the axis.
Lets start with x. The x intercept is always going to be what x equals when y = 0. So we know the second value of the x intercept is going to be 0, because the second value is y. The line hits the x axis at -1.2, so the x intercept is -1.2, 0
The y intercept it what y equals when x equals 0. So the first value is going to be 0, to represent x. The line hits the y intercept at the point 0, -0.7.
Answer:
<h2>C. g(x) = x - 6</h2>
Step-by-step explanation:
For a parent function y = f(x) and n > 0:
f(x) + n : move the graph n units up
f(x) - n : move the graph n units down
f(x + n) : move the graph n units to the left
f(x - n) : move the graph n units to the right
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We have
f(x) = x
Transformation: 6 units down
f(x) - 6 = x - 6
I'm not quite sure if this is what you need, but I am going to solve these equations by elimination. x= 8/17 and y = 11/17 (8/17, 11/17).
