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2 years ago

7 more than twice as many fruit loops is 5 less than triple the fruit loops

Mathematics

1 answer:

lara31 [8.8K]2 years ago

7 0

Answer:

What's the question lol ?

Step-by-step explanation:

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50 POINTS! Show All Work!

olasank [31]

Let the number of chickens = c.

Let the number of pigs = p.

A chicken has 1 head and 2 legs.

c number of chickens have c heads and 2c legs.

A pig has 1 head and 4 legs.

p number of pigs have p heads and 4p legs.

There are 40 heads.

Equation for heads:

c + p = 40

There are 110 legs.

Equation for legs:

2c + 4p = 110

System of equations:

c + p = 40

2c + 4p = 110

Solve the first equation of the system of equations for c:

c = 40 - p

Substitute 40 - p for c in the second equation:

2c + 4p = 110

2(40 - p) + 4p = 110

80 - 2p + 4p = 110

80 + 2p = 110

2p = 30

p = 15

Now substitute p = 15 in the first equation to find c.

c + p = 40

c + 15 = 40

c = 25

There are 25 chickens and 15 pigs.

7 0

2 years ago

Read 2 more answers

V<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20%2A%202%5Cfrac%7B1%7D%7B3%7D" id="TexFormula1" title="\frac{3}{4} * 2

myrzilka [38]

Answer:

$1\frac{3}{4}$

Step-by-step explanation:

In order to find the answer, you first need to convert the mixed number (2 1/3) into a improper fraction and then multiply.

$\frac{3}{4} \times2\frac{1}{3}$

$2\frac{1}{3} =3\times2=6+1=7=\frac{7}{3}$

$\frac{3}{4} \times\frac{7}{3}$

$3\times7=21$

$4\times3=12$

$=\frac{21}{12} =\frac{7}{4} =1\frac{3}{4}$

$=1\frac{3}{4}$

Hope this helps.

7 0

2 years ago

Helppppppopppppppppppppppppp

salantis [7]

B is a correct answer

6 0

2 years ago

The graph of f(x)=cos(x) is transformed to a new function, g(x), by stretching it horizontally by a factor of 4 and shifting it

pshichka [43]

I hope this helps you :)

4 0

1 year ago

A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past

Volgvan

Answer: We reject the null hypothesis, and we use Normal distribution for the test.

Step-by-step explanation:

Since we have given that

We claim that

Null hypothesis : $H_0:\mu\geq 50000$

Alternate hypothesis : $H_1:\mu$

There is 5% level of significance.

$\bar{X}=46800\\\\\sigma=9800\\\\n=29$

So, the test statistic would be

$z=\dfrac{\bar{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\z=\dfrac{46800-50000}{\dfrac{9800}{\sqrt{29}}}\\\\z=-1.75$

Since alternate hypothesis is left tailed test.

So, p-value = P(z≤-2.31)=0.0401

And the P-value =0.0401 is less than the given level of significance i.e. 5% 0.05.

So, we reject the null hypothesis, and we use Normal distribution for the test.

4 0

2 years ago